(9/(x^2-1))+(12/(3x+3))

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Solution for (9/(x^2-1))+(12/(3x+3)) equation: 


D( x )

x^2-1 = 0

3*x+3 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

3*x+3 = 0

3*x+3 = 0

3*x+3 = 0 // - 3

3*x = -3 // : 3

x = -3/3

x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

9/(x^2-1)+12/(3*x+3) = 0

(9*(3*x+3))/((x^2-1)*(3*x+3))+(12*(x^2-1))/((x^2-1)*(3*x+3)) = 0

9*(3*x+3)+12*(x^2-1) = 0

12*x^2+27*x+15 = 0

12*x^2+27*x+15 = 0

3*(4*x^2+9*x+5) = 0

4*x^2+9*x+5 = 0

DELTA = 9^2-(4*4*5)

DELTA = 1

DELTA > 0

x = (1^(1/2)-9)/(2*4) or x = (-1^(1/2)-9)/(2*4)

x = -1 or x = -5/4

3*(x+5/4)*(x+1) = 0

(3*(x+5/4)*(x+1))/((x^2-1)*(3*x+3)) = 0

(3*(x+5/4)*(x+1))/((x^2-1)*(3*x+3)) = 0 // * (x^2-1)*(3*x+3)

3*(x+5/4)*(x+1) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+5/4 )

x+5/4 = 0 // - 5/4

x = -5/4

x in { -1} 

x = -5/4

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